Beispielrechnungen
- 4 × π × 2² = 50,265482 m²
- 4 × π × 5² = 314,159265 m²
- 4 × π × 10² = 1.256,637061 m²
Oberfläche O = 4 × π × r².
113,097336 m²
Kugeloberfläche berechnen.
Oberfläche O = 4 × π × r².
| Radius | Ergebnis |
|---|---|
| 1 m | 12,566371 m² |
| 2 m | 50,265482 m² |
| 3 m | 113,097336 m² |
| 4 m | 201,06193 m² |
| 5 m | 314,159265 m² |
| 6 m | 452,389342 m² |
| 7 m | 615,75216 m² |
| 8 m | 804,247719 m² |
| 9 m | 1.017,87602 m² |
| 10 m | 1.256,637061 m² |
| 12 m | 1.809,557368 m² |
| 15 m | 2.827,433388 m² |
| 20 m | 5.026,548246 m² |
| 25 m | 7.853,981634 m² |
| 30 m | 11.309,733553 m² |
| 40 m | 20.106,192983 m² |
| 50 m | 31.415,926536 m² |
| 100 m | 125.663,706144 m² |